Question

What is the standard form of # y=(11x - x^2)(11 - x) #?

Answer 1

`x^3-22x^2+121x`

Explanation:

The way we solve this equation is by using the distributive property. Here is an example of how it works:

In this case, we multiply `(11x*11)+(11x*-x)+(-x^2*-11)+(-x^2*-x)`.
This becomes `121x+(-11x^2)+(-11x^2)+x^3`, which we can simplify to `121x-22x^2+x^3`.

Standard form is `ax^3+bx^2+cx+d`, so lets try to rewrite our expression in this form.
It gos from highest degree to lowest, so let's right it like that. `x^3-22x^2+121x+0`. We can ignore the zero, so we don't need to add it if we don't want to.

The final form is `x^3-22x^2+121x`