What is the standard form of $y= (2/5x^2-1/12)(1/3x+5/8)$ ?

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Answer 1 · 2016-02-16T13:16:23

$y=2x^3/15+x^2/4-x/36-5/96$

use the distribution property of multiplication over addition

$y=2/5x^2*(1/3x+5/8)-1/12*(1/3x+5/8)$
$y=2x^3/15+10x^2/40-x/36-5/96$

simplify some of the fractions to get

$y=2x^3/15+x^2/4-x/36-5/96$

hope it helps.. feel free to ask questions if you have any

Answer 2 · 2016-02-16T13:18:10

$(2/15)x^3+(1/4)x^2-(1/36)x-5/96$

As $y=(2/5x^2−1/12)(1/3x+5/8)$ is multiplication of one quadratic expression and one linear expression and hence of the form $ax^3+bx^2+cx+d$ .

So, multiplying $y=(2/5x^2−1/12)(1/3x+5/8)$ i.e.

$(2/5*1/3)x^3+(2/5*5/8)x^2-(1/12*1/3)x-(1/12*5/8)$

= $(2/15)x^3+(1/4)x^2-(1/36)x-5/96$

What is the standard form of y= (2/5x^2-1/12)(1/3x+5/8) y= (2/5x^2-1/12)(1/3x+5/8) ?