What is the standard form of $y= 2(7/5x + 14)^2 - 1$ ?

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Answer 1 · 2017-10-24T11:51:07

The expression can be standardized as:
$y = 98/25x² + 392/5x + 391$

To put the expression in the standard form, apply the power on the parentheses:

$y = 2 * (7/5 x + 14)^² - 1$
$y = 2 * (49/25x²+ 2 * (7/5x) * 14 + 196) - 1$
$y = 2 * (49/25x²+ 196/5x + 196) -1$

Now, multiply the inside of the parentheses by 2 (the number outside multiplying it):

$y = 98/25x² + 392/5x + 392 - 1 = 98/25x² + 392/5x + 391$

What is the standard form of y= 2(7/5x + 14)^2 - 1 y= 2(7/5x + 14)^2 - 1 ?