What is the standard form of $y = (- 2 x - \frac{1}{5}) (\frac{3}{7} x - 1)$ $y= (-2x-1/5)(3/7x-1)$ ?

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Answer 1 · 2015-11-19T03:35:48

Find standard form

$y = - (2 x + \frac{1}{5}) (\frac{3 x}{7} - 1)$ $y = -(2x + 1/5)((3x)/7 - 1)$ = -35(10x + 1)(3x - 7) #

$y = - 35 (30 x^{2} - 70 x + 3 x - 7) = - 35 (30 x^{2} - 67 x - 7)$ $y = -35(30x^2 - 70x + 3x - 7) = -35(30x^2 - 67x - 7)$

What is the standard form of y= (-2x-1/5)(3/7x-1) y=(−2x−15)(37x−1)y= (-2x-1/5)(3/7x-1) ?