What is the standard form of $y = {(2 x + 4)}^{2} - {(x - 7)}^{2}$ $y= (2x+4)^2-(x-7)^2$ ?

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What is the standard form of $y = {(2 x + 4)}^{2} - {(x - 7)}^{2}$ $y= (2x+4)^2-(x-7)^2$ ?

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Answer 1 · 2017-06-16T06:19:08

$y = 3 x^{2} + 30 x - 33$ $y=3x^2+30x-33$

Explanation:

Expand using the binomial theorem
$y = (4 x^{2} + 16 x + 16) - (x^{2} - 14 x + 49)$ $y=(4x^2+16x+16)-(x^2-14x+49)$
$y = 3 x^{2} + 30 x - 33$ $y=3x^2+30x-33$

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What is the standard form of $y = {(2 x + 4)}^{2} - {(x - 7)}^{2}$ $y= (2x+4)^2-(x-7)^2$ ?

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What is the standard form of y= (2x+4)^2-(x-7)^2 y=(2x+4)2−(x−7)2y= (2x+4)^2-(x-7)^2 ?

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What is the standard form of $y = {(2 x + 4)}^{2} - {(x - 7)}^{2}$ $y= (2x+4)^2-(x-7)^2$ ?