What is the standard form of $y= 2x(4x-2)(x-4)-x+2$ ?

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Answer 1 · 2018-04-11T08:36:29

Please look below.

First step is two expand the brackets:

$y = 2x(4x - 2)(x-4) -x + 2$

$y = (8x^2 - 4x)(x-4) -x+2$

$y = (8x^3 - 32x^2 - 16x^2 +16x) - x + 2$

Then simplify:

$y = 8x^3 - 48x^2+ 15 x + 2$

What is the standard form of y= 2x(4x-2)(x-4)-x+2y= 2x(4x-2)(x-4)-x+2?