What is the standard form of $y = (- 2 x - 5) (- x - 4)$ $y= (-2x-5)(-x-4)$ ?

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Answer 1 · 2016-02-09T04:32:38

Standard form is $y = a \cdot x^{2} + b \cdot x + c$ $y = a*x^2+b*x+c$

It is clearly observable that when right hand side is expanded, highest degree of $x$ $x$ is $a \cdot x^{2} + b \cdot x + c$ $a*x^2+b*x+c$

In fact this becomes $- 2 x \cdot (- x - 4) - 5 \cdot (- x - 4)$ $-2x*(-x-4)-5*(-x-4)$

i.e. $2 x^{2} + 8 x + 5 x + 20$ $2x^2+8x+5x+20$

i.e. $2 x^{2} + 13 x + 20$ $2x^2+13x+20$

From this it is obvious that the standard form is $y = a \cdot x^{2} + b \cdot x + c$ $y=a*x^2+b*x+c$

What is the standard form of y= (-2x-5)(-x-4) y=(−2x−5)(−x−4)y= (-2x-5)(-x-4) ?