What is the standard form of $y=(2x+7)(-3x-2) -4x^2-8$ ?

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Answer 1 · 2016-01-10T19:01:06

$y=-10x^2-25x-22$

Distribute the binomials using the FOIL method.

$y=overbrace(2x(-3x))^"First"+overbrace(2x(-2))^"Outside"+overbrace(7(-3x))^"Inside"+overbrace(7(-2))^"Last"-4x^2-8$

$y=-6x^2-4x-21x-14-4x^2-8$

Sort by term ( $x$ with $x$ , constants with constants):

$y=-6x^2-4x^2-4x-21x-14-8$

Combine like terms.

$y=-10x^2-25x-22$

This is in standard form since the exponents are in descending order.

What is the standard form of y=(2x+7)(-3x-2) -4x^2-8y=(2x+7)(-3x-2) -4x^2-8?