What is the standard form of y= (3/2x-4)^2+1?

1 Answer
Jul 14, 2018

y=9/4x^2-12x+17

Explanation:

"the standard form of a quadratic is ";ax^2+bx+c;a!=0

"to obtain this form expand and collect like terms"

y=(3/2x-4)(3/2x-4)+1

color(white)(y)=9/4x^2-6x-6x+16+1

color(white)(y)=9/4x^2-12x+17larrcolor(red)"in standard form"