What is the standard form of $y= (3x+1/2x^2)(6x-2)$ ?

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Answer 1 · 2018-04-19T08:58:17

$color(green)("Standard form is " y = 3x^3 + 17x^2 - 6x$

$y = (3x + x^2/2) * ( 6x - 2)$

$=> 18x^2 + 3x^3 - 6x - x^2$

$color(green)("Standard form is " y = 3x^3 + 17x^2 - 6x$

What is the standard form of y= (3x+1/2x^2)(6x-2) y= (3x+1/2x^2)(6x-2) ?