What is the standard form of $y= (3x^2-1)(2x-7) + (4x+1)^2$ ?

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Answer 1 · 2018-07-10T00:08:15

$y=6x^3-5x^2+6x+8$

Given:

$y=(3x^2-1)(2x-7)+(4x+1)^2$

Expand.

$y=6x^3-21x^2-2x+7+(4x+1)^2$

Expand.

$y=6x^3-21x^2-2x+7+16x^2+8x+1$

Collect like terms.

$y=6x^3+(-21x^2+16x^2)+(-2x+8x)+(7+1)$

Combine like terms.

$y=6x^3-5x^2+6x+8$

What is the standard form of y= (3x^2-1)(2x-7) + (4x+1)^2y= (3x^2-1)(2x-7) + (4x+1)^2?