What is the standard form of $y = 3 x (2 x - 6) (3 x - 2)$ $y= 3x(2x-6)(3x-2)$ ?

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Answer 1 · 2018-06-15T09:01:11

$y = 18 x^{3} - 66 x^{2} + 36 x, or 6 (3 x^{3} - 11 x^{2} + 6 x)$ $color(blue)(y = 18x^3 - 66x^2 + 36x, " or " 6(3x^3- 11x^2 + 6x)$

$Standard form is y = a x^{3} + b x^{2} + c x + d, a \neq 0$ $"Standard form is " y = ax^3 + bx^2 + cx + d, a!= 0$

$y = 3 x (2 x - 6) (3 x - 2)$ $y = 3x(2x-6)(3x-2)$

$y = (6 x^{2} - 18 x) \cdot (3 x - 2)$ $y = (6x^2 -18x)*(3x-2)$

$y = 18 x^{3} - 54 x^{2} - 12 x^{2} + 36 x$ $y = 18x^3 -54x^2 - 12x^2 + 36x$

$y = 18 x^{3} - 66 x^{2} + 36 x, or 6 (3 x^{3} - 11 x^{2} + 6 x)$ $color(blue)(y = 18x^3 - 66x^2 + 36x, " or " 6(3x^3- 11x^2 + 6x)$

What is the standard form of y= 3x(2x-6)(3x-2)y=3x(2x−6)(3x−2)y= 3x(2x-6)(3x-2)?