Question

What is the standard form of `y=(3x-5)(2x+11)`?

Answer 1

`y=6x^2+23x-55`

Explanation:

Standard form is `y=ax^2+bx+c`

So you want to multiply the two factors together.
You can use Foil where you multiply the first two terms then the outer, inner, and last terms. Then add them together

`3x*2x=6x`

`3x*11=33x`

`-5*2x=-10x`

`-5*11=-55`

`y=6x^2+33x+(-10x)+(-55)`

Combine like terms

`y=6x^2+23x-55`