What is the standard form of $y= (3x-5)(2x+12)-7x^2+15x$ ?

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Answer 1 · 2016-01-15T11:39:52

$y = -x^2+41x -60$

To get the standard form, multiply out to get rid of the brackets and then group the like items and order in descending order of powers.

$y=(6x^2 -10x+36x-60) - 7x^2 +15x$
$y = -x^2+41x -60$

What is the standard form of y= (3x-5)(2x+12)-7x^2+15x y= (3x-5)(2x+12)-7x^2+15x?