What is the standard form of $y=(3x-5)(6x-2)$ ?

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Answer 1 · 2016-02-04T05:52:57

$y = 18x^2 - 36x + 10$

The standard form of an equation is:
$y = ax^2 - bx + c$

So, you have to develop the right member which is the form :
$(a + b) (c + d)$
We develop as :
$(a*c) + (a*d) + (b*c) + (b*d)$

So :
$y = (3x - 5)(6x-2)$
$y = (3x * 6x) + (3x * -2) + (- 5 * 6x) + (-5 * -2)$
$y = 18x^2 - 6x -30x + 10$
$y = 18x^2 - 36x + 10$

What is the standard form of y=(3x-5)(6x-2)y=(3x-5)(6x-2)?