What is the standard form of $y= 3x(x-3)+(2-x)(x-4/5)$ ?

Question

1918 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-23T15:23:04

$10x^2-31x-5y-8=0$

$y=3x(x-3)+(2-x)(x-4/5)$

Use the distributive property

$y=3x^2-9x+2x-8/5-x^2+(4x)/5$

$y=2x^2-31/5x-8/5$

Then multiply the whole equation with 5

$(y=2x^2-31/5x-8/5)*5$

$5y=10x^2-31x-8$

$5y-10x^2+31x+8=0$

$10x^2-31x-5y-8=0$ And this is the final standard answer

What is the standard form of y= 3x(x-3)+(2-x)(x-4/5) y= 3x(x-3)+(2-x)(x-4/5) ?