What is the standard form of y= (4x-2x^2)(4x-3) -(x+2)^3y=(4x−2x2)(4x−3)−(x+2)3?

1 Answer
SCooke
Nov 27, 2017

"Standard form" for a polynomial is with all the factors worked out and arranged from highest to lowest exponent.
y = -9x^3 + 16x^2 - 24x - 8y=−9x3+16x2−24x−8

Explanation:

First, we combine the factors:
y = (4x−2x^2)(4x−3) − (x + 2)^3y=(4x−2x2)(4x−3)−(x+2)3
y = (16x^2 - 8x^3 - 12x + 6x^2) − (x^3 + 4x^2 + 4x + 2x^2 + 8x + 8)y=(16x2−8x3−12x+6x2)−(x3+4x2+4x+2x2+8x+8)

y = -9x^3 + 16x^2 - 24x - 8y=−9x3+16x2−24x−8

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