What is the standard form of # y= (4x-4)(6x-2)(8x-4)#? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Abdullah M. Oct 21, 2017 #y=96x^3-128x+32# Explanation: y = (4x-4)(6x-2)(8x-4) #=(24x^2-32x+8)*(8x-4)# #=(192x^3-256x+64x-96x^3+128x-32)# #=(96x^3-128x+32)# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1766 views around the world You can reuse this answer Creative Commons License