What is the standard form of $y = (4 x - 4) (6 x - 2) (8 x - 4)$ $y= (4x-4)(6x-2)(8x-4)$ ?

Question

What is the standard form of $y = (4 x - 4) (6 x - 2) (8 x - 4)$ $y= (4x-4)(6x-2)(8x-4)$ ?

1 Answer

Impact of this question

2009 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-21T06:21:47

$y = 96 x^{3} - 128 x + 32$ $y=96x^3-128x+32$

Explanation:

y = (4x-4)(6x-2)(8x-4)

$= (24 x^{2} - 32 x + 8) \cdot (8 x - 4)$ $=(24x^2-32x+8)*(8x-4)$
$= (192 x^{3} - 256 x + 64 x - 96 x^{3} + 128 x - 32)$ $=(192x^3-256x+64x-96x^3+128x-32)$
$= (96 x^{3} - 128 x + 32)$ $=(96x^3-128x+32)$

Science

Math

Humanities

... and beyond

What is the standard form of $y = (4 x - 4) (6 x - 2) (8 x - 4)$ $y= (4x-4)(6x-2)(8x-4)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the standard form of y=(4x−4)(6x−2)(8x−4) y= (4x-4)(6x-2)(8x-4)?

1 Answer

Explanation:

Related questions

Impact of this question

What is the standard form of $y = (4 x - 4) (6 x - 2) (8 x - 4)$ $y= (4x-4)(6x-2)(8x-4)$ ?