What is the standard form of y=5(x-3)^2-7y=5(x−3)2−7?

1 Answer
radee
Jan 27, 2016

y = 5x^2 - 30x + 38y=5x2−30x+38

Explanation:

Since this is a quadratic equation, the standard form should appear this way

y = ax^2 + bx + cy=ax2+bx+c

In this case, you will have to expand and simplify (if possible) the equation to get the standard form.

[Solution]
y = 5(x - 3)^2 - 7y=5(x−3)2−7
y = 5(x^2 - 6x + 9) - 7y=5(x2−6x+9)−7
y = 5x^2 - 30x + 45 - 7y=5x2−30x+45−7
y = 5x^2 - 30x + 38y=5x2−30x+38

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