What is the standard form of $y= (6x-7)(6x-2)(1/6x-1/49)$ ?

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Answer 1 · 2016-06-19T10:33:52

I got: $y=6x^3 -447/49x^2+505/147x-2/7$

$color(blue)("Multiply the last 2 brackets because "6/6 x=x)$
Consider: $" "(6x-2)(1/6x-1/49)$

= $x^2-6/49x-2/6x +2/49" " =" "x^2-67/147x+2/49$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(blue)("Multiply by the first bracket")$

$=(6x-7)(x^2-67/147x+2/49)$

$=6x^3-134/49x^2 +12/49x" "-7x^2+67/21x-2/7$

$=6x^3 -447/49x^2+505/147x-2/7$

What is the standard form of y= (6x-7)(6x-2)(1/6x-1/49) y= (6x-7)(6x-2)(1/6x-1/49)?