Question

What is the standard form of `y= (9x-2)(x+2)(7x-4)`?

Answer 1

`y=63x^3-148x^2+50x+8`

Explanation:

The standard form refers to the format of an expression where the terms are arranged in a descending order. The degree is determined by the exponent value of the variable of each term.

To find the standard form, multiply the brackets out and simplify.

`y=(9x-2)(x+2)(7x-4)`

Lets multiply out `y=(9x-2)(x+2)` first:

`y=(9x-2)(x+2)`
`y=9x^2+18x-2x-2`
`y=9x^2-16x-2`

Then multiply `y=(9x^2-16x-2)(7x-4)`:

`y=(9x^2-16x-2)(7x-4)`
`y=63x^3-36x^2-112x^2+64x-14x+8`
`y=63x^3-148x^2+50x+8`

This is the standard form.