What is the standard form of #y=(-x - 1) (3x - 2) (4x + 1) #?

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Answer 1 · 2016-02-03T15:00:27

#y=(-x-1)(3x-2)(4x+1)#

First multiply the two binomials using FOIL method:

#ulF#irsts
#ulO#utsides
#ulI#nsides
#ulL#asts

So,

#rarr(-x-1)(3x-2)=-3x^2+2x-3x+2=(-3x^2-x+2)#

Now multiply:

#(-3x^2-x+2)(4x+1)#

Use the distributive law and multiply:

#rarry=-12x^3-7x^2+7x+2#