What is the standard form of y= (-x+1)(-3x-2)(6x-1)?

1 Answer

y=18x^3-9x^2-11x+2

Explanation:

The given seems like the factored form
y=(-x+1)(-3x-2)(6x-1)

For what I know, standard form is that kind of arrangement of the terms from highest degree to the lowest degree term after multiplying all these factors.

y=(-x+1)(-3x-2)(6x-1)

multiply the first two factors
y=(3x^2+2x-3x-2)(6x-1)
simplify by combining similar terms
y=(3x^2-x-2)(6x-1)
multiply the remaining factors
y=18x^3-6x^2-12x-3x^2+x+2
simplify again to obtain the final answer. Make sure the terms are arranged from highest to lowest degree
y=18x^3-9x^2-11x+2

God bless....I hope the explanation is useful.