What is the standard form of y= (x-2/3)(3/4x-12) y=(x−23)(34x−12)?

1 Answer
Jim G.
Jan 26, 2016

3/4 x^2 - 25/2 x + 8 34x2−252x+8

Explanation:

Distribute using FOIL

x xx 3/4 x - 12x - (2/3 xx 3/4 x ) + ( 12 xx 2/3 ) x×34x−12x−(23×34x)+(12×23)

= 3/4 x^2 - 12x - ( cancel(2)/cancel(3) xx cancel(3)/cancel(4) x )+(cancel(12) xx 2/cancel(3) )

= 3/4 x^2 - 12x -1/2 x + 8 = 3/4 x^2 - 25/2 x + 8

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