What is the standard form of $y = (x - 2) (3 x + 2) (- x + 8)$ $y= (x-2)(3x+2)(-x+8)$ ?

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What is the standard form of $y = (x - 2) (3 x + 2) (- x + 8)$ $y= (x-2)(3x+2)(-x+8)$ ?

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Answer 1 · 2017-12-10T11:11:48

$- 3 x^{3} + 28 x^{2} - 28 x - 32$ $-3x^3+28x^2-28x-32$

Explanation:

$expand the first 2 factors using FOIL then multiply the$ $"expand the first 2 factors using FOIL then multiply the"$
$result by the third factor$ $"result by the third factor"$

$(x - 2) (3 x + 2) \leftarrow first 2 factors$ $(x-2)(3x+2)larrcolor(blue)"first 2 factors"$

$= 3 x^{2} + 2 x - 6 x - 4$ $=3x^2+2x-6x-4$

$= 3 x^{2} - 4 x - 4$ $=3x^2-4x-4$

$\Rightarrow (3 x^{2} - 4 x - 4) (- x + 8) \leftarrow multiply by third factor$ $rArr(3x^2-4x-4)(-x+8)larrcolor(blue)"multiply by third factor"$

$= - 3 x^{3} + 24 x^{2} + 4 x^{2} - 32 x + 4 x - 32$ $=-3x^3+24x^2+4x^2-32x+4x-32$

$= - 3 x^{3} + 28 x^{2} - 28 x - 32 \leftarrow in standard form$ $=-3x^3+28x^2-28x-32larrcolor(blue)"in standard form"$

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What is the standard form of $y = (x - 2) (3 x + 2) (- x + 8)$ $y= (x-2)(3x+2)(-x+8)$ ?

1 Answer

Explanation:

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What is the standard form of y= (x-2)(3x+2)(-x+8)y=(x−2)(3x+2)(−x+8) y= (x-2)(3x+2)(-x+8)?

1 Answer

Explanation:

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What is the standard form of $y = (x - 2) (3 x + 2) (- x + 8)$ $y= (x-2)(3x+2)(-x+8)$ ?