What is the standard form of $y = (- x + 2) (7 x + 4)$ $y= (-x + 2)(7x + 4 )$ ?

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Answer 1 · 2016-02-14T10:51:25

$y = 7 x^{2} - 10 x + 8$ $y=7x^2-10x+8$

$y = (- x + 2) (7 x + 4)$ $y=(-x+2)(7x+4)$

First we can multiply the two binomials using the FOIL method:

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$ul First=-x*7x=-7x^2$

$ul Outer=-x*4=-4x$

$ul I$ $n$ $n$ $er=2*7x=14x$

$ul Las$ $t=2*4=8$

Now combine them:

$rarr-7x^2-4x+14x+8$

$rarr=-7x^2-10x+8$

So in Standard form:

$rArry=-7x^2-10x+8$

Answer 2 · 2016-02-14T10:53:03

Standard form of $y=(−x+2)(7x+4)$ is $y=ax^2+bx+c$

Expanding $y=(−x+2)(7x+4)$

$y=-7x^2+14x-4x+8$ or $y=-7x^2+10x+8$

Hence standard form of $y=(−x+2)(7x+4)$ is $y=ax^2+bx+c$

What is the standard form of y= (-x + 2)(7x + 4 ) y=(−x+2)(7x+4)y= (-x + 2)(7x + 4 ) ?