What is the standard form of $y=(x^3 - 8)(x-2)$ ?

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Answer 1 · 2016-01-20T09:28:55

$x^4 - 2x^3 - 8x + 16$

multiply out the brackets ( distributive law ) and 'collect like terms '

$x^3(x - 2 ) - 8 (x - 2 )$

$= x^4 -2 x^3 - 8x + 16$

What is the standard form of y=(x^3 - 8)(x-2) y=(x^3 - 8)(x-2) ?