What is the standard form of $y = (x^{3} - 8) (x - 2)$ $y=(x^3 - 8)(x-2)$ ?

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What is the standard form of $y = (x^{3} - 8) (x - 2)$ $y=(x^3 - 8)(x-2)$ ?

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Answer 1 · 2016-01-20T09:28:55

$x^{4} - 2 x^{3} - 8 x + 16$ $x^4 - 2x^3 - 8x + 16$

Explanation:

multiply out the brackets ( distributive law ) and 'collect like terms '

$x^{3} (x - 2) - 8 (x - 2)$ $x^3(x - 2 ) - 8 (x - 2 )$

$= x^{4} - 2 x^{3} - 8 x + 16$ $= x^4 -2 x^3 - 8x + 16$

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What is the standard form of $y = (x^{3} - 8) (x - 2)$ $y=(x^3 - 8)(x-2)$ ?

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Science

Math

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What is the standard form of y=(x3−8)(x−2)y=(x^3 - 8)(x-2) ?

1 Answer

Explanation:

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What is the standard form of $y = (x^{3} - 8) (x - 2)$ $y=(x^3 - 8)(x-2)$ ?