What is the standard form of $y = x^{3} (9 x^{2} - x - 3)$ $y=x^3(9x^2-x-3)$ ?

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Answer 1 · 2018-07-09T23:28:26

$9 x^{5} - x^{4} - 3 x^{3}$ $9x^5-x^4-3x^3$

Let's start by distributing the $x^{3}$ $x^3$ to all terms. Remember, when we multiply exponents, we add the powers. We get

$9 x^{5} - x^{4} - 3 x^{3}$ $9x^5-x^4-3x^3$

Since our exponents are in order of descending degree, we are in standard form!

Hope this helps!

What is the standard form of y=x3(9x2−x−3) y=x^3(9x^2-x-3) ?