What is the standard form of $y= (x+3)(-x-1)+(3x-7)^2$ ?

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Answer 1 · 2016-02-19T12:41:18

$8x^2-46x+46$

It is apparent that the highest degree of $x$ in the function

$(x+3)(−x−1)+(3x−7)^2$ is two. Expanding the function

$(x+3)(−x−1)+(3x−7)(3x-7)$

$(x+3)(−x)−1(x+3)+3x(3x-7)-7(3x-7)$ or

$-x^2-3x-x-3+9x^2-21x-21x+49$ or

$8x^2-46x+46$

As it is an function in degree $2$ of form $ax^2+bx+c$

What is the standard form of y= (x+3)(-x-1)+(3x-7)^2 y= (x+3)(-x-1)+(3x-7)^2?