What is the standard form of $y = (x + 4) (2 x - 2) - {(5 x - 2)}^{2}$ $y= (x+4)(2x-2)-(5x-2)^2$ ?

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What is the standard form of $y = (x + 4) (2 x - 2) - {(5 x - 2)}^{2}$ $y= (x+4)(2x-2)-(5x-2)^2$ ?

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Answer 1 · 2018-05-25T02:03:39

$y = - 23 x^{2} + 26 x - 12$ $y= -23x^2+26x-12$

Explanation:

$y = (x + 4) (2 x - 2) - {(5 x - 2)}^{2}$ $y=(x+4)(2x-2)-(5x-2)^2$
$y = x (2 x - 2) + 4 (2 x - 2) - [(5 x - 2) (5 x - 2)]$ $y=x(2x-2)+4(2x-2)-[(5x-2)(5x-2)]$
$y = 2 x^{2} - 2 x + 8 x - 8 - [5 x (5 x - 2) - 2 (5 x - 2)]$ $y=2x^2-2x+8x-8-[5x(5x-2)-2(5x-2)]$
$y = 2 x^{2} - 2 x + 8 x - 8 - [25 x^{2} - 20 x + 4]$ $y=2x^2-2x+8x-8-[25x^2-20x+4]$
$y = 2 x^{2} - 2 x + 8 x - 8 - 25 x^{2} + 20 x - 4$ $y=2x^2-2x+8x-8-25x^2+20x-4$
$y = - 23 x^{2} + 26 x - 12$ $y=-23x^2+26x-12$
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What is the standard form of $y = (x + 4) (2 x - 2) - {(5 x - 2)}^{2}$ $y= (x+4)(2x-2)-(5x-2)^2$ ?

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What is the standard form of $y = (x + 4) (2 x - 2) - {(5 x - 2)}^{2}$ $y= (x+4)(2x-2)-(5x-2)^2$ ?