What is the standard form of $y= (x - 5)^2(6-x)$ ?

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Answer 1 · 2015-12-17T03:45:33

$y=-x^3+16x^2-50x+150$

First expand $(x-5)^2$ .

$(x-5)^2=(x-5)(x-5)=x^2-10x+25$

Now, you know that $y=(x^2-10x+25)(6-x)$

Distribute again.

$y=6x^2-60x+150-x^3+10x^2-25x$

Combine like terms and write the terms in order of descending degree (biggest exponent first).

$y=-x^3+16x^2-50x+150$

What is the standard form of y= (x - 5)^2(6-x)y= (x - 5)^2(6-x)?