What is the standard form of #y= (x - 5)^2(6-x)#?

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Answer 1 · 2015-12-17T03:45:33

#y=-x^3+16x^2-50x+150#

First expand #(x-5)^2#.

#(x-5)^2=(x-5)(x-5)=x^2-10x+25#

Now, you know that #y=(x^2-10x+25)(6-x)#

Distribute again.

#y=6x^2-60x+150-x^3+10x^2-25x#

Combine like terms and write the terms in order of descending degree (biggest exponent first).

#y=-x^3+16x^2-50x+150#