to put something in standard form means to put it in order from exponent, then just #x# then the number. so for this one, you have to distribute #x# to the next #x# and #2# so you'll get #x^2+2x# then the second number#-6x-12# you don't do the second number b/c it's the one being distributed to and plus it'll be the same. so now put it together and add like terms. #x^2# is by itself. so do #+2x-6x# and #-12# is alone b/c there's nothing else like it. so you have #x^2-4x-12# and don't do #-6+2# so it EXACTLY like it is when you distribute
