What is the standard form of $y= (x+7)(x+1)-(3x-7)^2$ ?

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Answer 1 · 2016-03-28T06:30:10

$y=-8x^2+50x-42$

From the given equation
$y=(x+7)(x+1)-(3x-7)^2$

We start by expanding the right side using multiplication

$y=x^2+8x+7-(9x^2-42x+49)$

$y=x^2+8x+7-9x^2+42x-49$

Simplify

$y=-8x^2+50x-42$

graph{y=(x+7)(x+1)-(3x-7)^2[-80,80,-40,40]}

God bless....I hope the explanation is useful.

What is the standard form of y= (x+7)(x+1)-(3x-7)^2 y= (x+7)(x+1)-(3x-7)^2?