What is the value of #k#, where #k=(1+1/n)^n#, given #n# is equals to number of seconds in one year? (a). #e# (b). 2.7 (c). 2 (d). 2.75

1 Answer
Sep 28, 2017

Very close to the value of e

Explanation:

Value of #n# = number of seconds in one year.

Seconds in one year is:

Number of days in year X number of hours in one day X number of minutes in one hour X number of seconds in one minute.

#365 xx 24 xx 60xx60 = 31536000#

So:

#k = (1+1/n)^n=> k= (1+1/ 31536000)^ 31536000# => k= 2.7182817853609708213. (20 significant digits).

Value of #e = 2.7182818284590452354# (20 significant digits).