What is the vertex form of #1y=7x^2 + 5x - 11?

1 Answer
Nghi N.
Dec 17, 2015

Find vertex of y = 7x^2 + 5x - 11

Vertex (-5/14, 1981/146)

Explanation:

x-coordinate of vertex: x = (-b)/2a = -5/14
y-coordinate of vertex:
y = y(-5/14) = 7(25/196) + 5(-5/14) - 11 = = 175/196 - 25/14 - 11 = 1981/196
Vertex form: y = 7(x + 5/14)^2 + 1981/196

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