What is the vertex form of $3y = - 3x^2 + 12x + 7$ ?

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Answer 1 · 2018-07-09T09:39:36

$(x-2)^2=-(y-19/3)$

Given quadratic equation:

$3y=-3x^2+12x+7$

$3y=-3(x^2-4x)+7$

$3y=-3(x^2-4x+4)+12+7$

$3y=-3(x-2)^2+19$

$y=-(x-2)^2+19/3$

$(x-2)^2=-(y-19/3)$

Above is the vertex form of parabola which represents a downward parabola with the vertex at

$(x-2=0, y-19/3=0)\equiv(2, 19/3)$

What is the vertex form of 3y = - 3x^2 + 12x + 7 3y = - 3x^2 + 12x + 7 ?