What is the vertex form of #3y=4x^2 + 9x - 1?

1 Answer
Oct 18, 2017

y=color(green)(4/3)(x-color(red)((-9/8)))^2+color(blue)(""(-81/48))
with vertex at (color(red)(-9/8),color(blue)(-81/48))

Explanation:

Remember our target form is y=color(green)m(x-color(red)a)^2+color(blue)b
with vertex at (color(red)a,color(blue)b)

3y=4x^2+9x-1

rarr y=color(green)(4/3)x^2+3x-1/3

rarr y=color(green)(4/3)(x^2+9/4x)-1/3

rarr y=color(green)(4/3)(x^2+9/4xcolor(magenta)(+(9/8)^2))-1/3color(white)("xx")color(magenta)(-color(green)(4/3)*(9/8)^2)

rarr y=color(green)(4/3)(x+9/8)^2-1/3-27/16

rarr y=color(green)(4/3)(x-color(red)((-9/8)))^2-16/48-81/48

rarr y=color(green)(4/3)(x-color(red)((-9/8)))^2+color(blue)((-97/48))

which is the vertex form with vertex at (color(red)(-9/8),color(blue)(-97/48))

I admit this is not very pretty, so here is a graph of the given equation to demonstrate that this answer is at least reasonable:
enter image source here