What is the vertex form of $3y = 5x^2+5x-12$ ?

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Answer 1 · 2016-04-19T11:35:05

$y=5/3(x+1/2)^2-53/12$

$y=5/3*x^2+5/3*x-4=5/3(x^2+x+1/4)-5/12-4=5/3(x+1/2)^2-53/12$ Vertex is at $(-1/2,-53/12)$ graph{5/3x^2+5/3x-4 [-10, 10, -5, 5]}[Ans]

What is the vertex form of 3y = 5x^2+5x-123y = 5x^2+5x-12?