What is the vertex form of 7y = - 13x^2 -15x + 2 ?

1 Answer
Feb 13, 2016

y=-13/7(x+15/26)^2+329/364

Explanation:

First, get the equation into its typical form by dividing both sides by 7.

y=-13/7x^2-15/7x+2/7

Now, we want to get this into vertex form:

y=a(x-h)^2+k

First, factor the -13/7 from the first two terms. Note that factoring a -13/7 from a term is the same as multiplying the term by -7/13.

y=-13/7(x^2+15/13x)+2/7

Now, we want the term in the parentheses to be a perfect square. Perfect squares come in the pattern (x+a)^2=x^2+2ax+a^2.

Here, the middle term 15/13x is the middle term of the perfect square trinomial, 2ax. If we want to determine what a is, divide 15/13x by 2x to see that a=15/26.

This means that we want to add the missing term in the parentheses to make the group equal to (x+15/26)^2.

y=-13/7overbrace((x^2+15/13x+?))^((x+15/26)^2)+2/7

The missing term at the end of the perfect square trinomial is a^2, and we know that a=15/26, so a^2=225/676.

Now we add 225/676 to the terms in the parentheses. However, we can't go adding numbers to equations willy-nilly. We must balance what we just added on the same side of the equation. (For example, if we had added 2, we would need to add -2 to the same side of the equation for a net change of 0).

y=color(blue)(-13/7)(x^2+15/13x+color(blue)(225/676))+2/7+color(blue)?

Notice that we haven't actually added 225/676. Since it's inside of the parentheses, the term on the outside is being multiplied in. Thus, the 225/676 actually has a value of

225/676xx-13/7=225/52xx-1/7=-225/364

Since we have actually added -225/364, we must add a positive 225/364 to the same side.

y=-13/7(x+15/26)^2+2/7+225/364

Note that 2/7=104/364, so

color(red)(y=-13/7(x+15/26)^2+329/364

This is in vertex form, where the parabola's vertex is at (h,k)->(-15/26,329/364).

We can check our work by graphing the parabola:

graph{7y = - 13x^2 -15x + 2 [-4.93, 4.934, -2.466, 2.466]}

Note that -15/26=-0.577 and 329/364=0.904, which are the values obtained by clicking on the vertex.