What is the vertex form of $7 y = (x - 3) (4 x + 2)$ $7y=(x − 3)(4x + 2)$ ?

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Answer 1 · 2017-06-06T04:48:37

$y = \frac{4}{7} {(x - \frac{5}{4})}^{2} - \frac{7}{4}$ $y = 4/7(x- 5/4)^2 - 7/4$

$7 y = (x - 3) (4 x + 2)$ $7y = (x-3)(4x+2)$

$y = \frac{1}{7} \cdot 4 \cdot (x - 3) (x + \frac{1}{2})$ $y = 1/7 * 4 * (x-3)(x+ 1/2 )$

$y = \frac{4}{7} (x^{2} - \frac{5}{2} x - \frac{3}{2})$ $y = 4/7 (x^2-5/2 x - 3/2)$

$y = \frac{4}{7} [{(x - \frac{5}{4})}^{2} - \frac{49}{16}]$ $y = 4/7 [(x- 5/4)^2 - 49/16]$

$y = \frac{4}{7} {(x - \frac{5}{4})}^{2} - \frac{7}{4}$ $y = 4/7(x- 5/4)^2 - 7/4$

What is the vertex form of 7y=(x − 3)(4x + 2) 7y=(x−3)(4x+2)7y=(x − 3)(4x + 2) ?