What is the vertex form of $f(x) = 6x^2+4x-3$ ?

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Answer 1 · 2017-02-01T08:54:47

The answer is $=6(x+1/3)^2-11/9$

We look for the vertex form by completing the squares

$f(x)=6x^2+4x-3$

$=6(x^2+4/6x)-3$

$=6(x^2+2/3x+1/9)-3-6/9$

$=6(x+1/3)^2-11/9$

This is the vertex form

What is the vertex form of f(x) = 6x^2+4x-3 f(x) = 6x^2+4x-3 ?