What is the vertex form of f(x) = -x^2 -x-2 f(x)=−x2−x−2?

1 Answer
Binayaka C.
May 18, 2017

The vertex form of equation is f(x) = - (x+ 0.5)^2 -1.75f(x)=−(x+0.5)2−1.75

Explanation:

f(x)= - x^2-x-2 = - (x^2 +x) -2 = - (x^2 +x +(1/2)^2) +1/4-2f(x)=−x2−x−2=−(x2+x)−2=−(x2+x+(12)2)+14−2

f(x)= - (x +1/2)^2 -7/4 or f(x) = - (x+ 0.5)^2 -1.75f(x)=−(x+12)2−74orf(x)=−(x+0.5)2−1.75

Comparing with general vertex form of equation,

f(x) = a(x-h)^2+k ; (h,k) f(x)=a(x−h)2+k;(h,k) being vertex, here vertex is at (-0.5 , -1.75)(−0.5,−1.75)

The vertex form of equation is f(x) = - (x+ 0.5)^2 -1.75f(x)=−(x+0.5)2−1.75 [Ans]

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