What is the vertex form of x= 4y^2 + 16y + 16?

1 Answer
Jul 25, 2017

See a solution process below:

Explanation:

To convert a quadratic from x = ay^2 + by + c form to vertex form, x = a(y - color(red)(h))^2+ color(blue)(k), you use the process of completing the square.

This equation is already a perfect square. We can factor out a 4 and complete the square:

x = 4y^2 + 16y + 16 - color(red)(16)

x = 4(y^2 + 4y + 4)

x = 4(y + 2)^2

Or, in precise form:

x = 4(y + (-2))^2 + 0