What is the vertex form of x = (y - 3)^2 + 41?

1 Answer
Aug 3, 2017

x = (y - 3)^2 + 41 is in the vertex form.

Explanation:

The vertex form for a parabola that opens to the left or right is:

x = 1/(4f)(y-k)^2+h" [1]"

where (h,k) is the vertex and f = y_"focus"-k.

The given equation

x = (y - 3)^2 + 41

is already in the form of equation [1] where (h,k) = (41,3) and f = 1/4.