Question

What is the vertex form of `x = (y - 3)^2 + 41`?

Answer 1

`x = (y - 3)^2 + 41` is in the vertex form.

Explanation:

The vertex form for a parabola that opens to the left or right is:

`x = 1/(4f)(y-k)^2+h" [1]"`

where `(h,k)` is the vertex and `f = y_"focus"-k`.

The given equation

`x = (y - 3)^2 + 41`

is already in the form of equation [1] where `(h,k) = (41,3) and f = 1/4`.