What is the vertex form of y= 1/2x^2 + 3/2x -4?

1 Answer
Apr 30, 2017

"The vertex form is : "y=1/2(x+3/2)^2-41/8

Explanation:

"The vertex form is formed as y="a(x-h)^2+k

"Where (h,k) is vertex coordinates"

"we should rearrange the given equation."

y=1/2x^2+3/2x-4

y=1/2x^2+3/2xcolor(red)(+9/8-9/8)-4

y=1/2(color(green)(x^2+3x+9/4))-9/8-4

color(green)(x^2+3x+9/4)=(x+3/2)^2

y=1/2(x+3/2)^2-41/8