What is the vertex form of #y= 1/2x^2 + 3/2x -4#?

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Answer 1 · 2017-04-30T20:10:05

#"The vertex form is : "y=1/2(x+3/2)^2-41/8#

#"The vertex form is formed as y="a(x-h)^2+k#

#"Where (h,k) is vertex coordinates"#

#"we should rearrange the given equation."#

#y=1/2x^2+3/2x-4#

#y=1/2x^2+3/2xcolor(red)(+9/8-9/8)-4#

#y=1/2(color(green)(x^2+3x+9/4))-9/8-4#

#color(green)(x^2+3x+9/4)=(x+3/2)^2#

#y=1/2(x+3/2)^2-41/8#