What is the vertex form of $y=11x^2 - 4x + 31$ ?

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Answer 1 · 2017-10-22T11:41:28

The vertex form of equation is $y= 11(x-2/11)^2 +30 7/11$
of which vertex is at $(2/11 , 30 7/11$ )

$y= 11x^2-4x+31 or y= 11(x^2-4/11x) +31$ or

$y= 11(x^2-4/11x +(2/11)^2)- 11*4/11^2 +31$ or

$y= 11(x-2/11)^2- 4/11 +31$ or

$y= 11(x-2/11)^2 +337/11$ or

$y= 11(x-2/11)^2 +30 7/11$

The vertex form of equation is $y= 11(x-2/11)^2 +30 7/11$

of which vertex is at $(2/11 , 30 7/11$ ) [Ans]

What is the vertex form of y=11x^2 - 4x + 31 y=11x^2 - 4x + 31 ?