Question

What is the vertex form of `y = 12x^2 -12x + 16`?

Answer 1

Vertex form of equation is `y=12(x-1/2)^2+13`

Explanation:

`y=12x^2-12x+16=12(x^2-x)+16 =12(x^2-x+(1/2)^2)-3+16=12(x-1/2)^2+13 :.`Vertex is at `(1/2,13)`& vertex form of equation is `y=12(x-1/2)^2+13 :.` graph{12x^2-12x+16 [-80, 80, -40, 40]}[Ans]