What is the vertex form of y= 12x^2-14x-6 ?

1 Answer
Apr 8, 2017

y=12(x-7/12)^2-121/12

Explanation:

The equation of a parabola in color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
where (h ,k) are the coordinates of the vertex and a is constant.

"Rearrange " y=12x^2-14x-6" into this form"

"Using the method of "color(blue)"completing the square"

y=12(x^2-7/6x-1/2)larr" coefficient of " x^2" is unity"

y=12[(x^2-7/6xcolor(red)(+49/144))color(red)(-49/144)-1/2]

color(white)(y)=12[(x-7/12)^2-121/144]

rArry=12(x-7/12)^2-121/12larrcolor(red)" in vertex form"