What is the vertex form of $y = 12x^2 -4x + 6$ ?

Question

2035 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-23T04:55:59

$y=12(x-1/6)^2+17/3$

$y=12x^2-4x+6$

Factor out the $a$ value to make the numbers smaller and easier to use:
$y=12[x^2-1/3x+1/2]$

Rewrite what's inside the brackets by completing the square
$y=12[(x-1/6)^2+(1/2-1/36)]$

$y=12[(x-1/6)^2+17/36]$

Finally distribute the 12 back
$y=12(x-1/6)^2+17/3$

What is the vertex form of y = 12x^2 -4x + 6y = 12x^2 -4x + 6?