What is the vertex form of $y=13x^2 + 14x + 24$ ?

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Answer 1 · 2018-07-17T11:07:17

Vertex form of equation is $y=13( x+7/13)^2-20 3/13$

$y=13 x^2+14 x+24$ or

$y=13 (x^2+14/13 x)+24$ or

$y=13 {x^2+14/13 x+(7/13)^2}-49/13+24$ or

$y=13( x+7/13)^2-263/13$ or

$y=13( x+7/13)^2-20 3/13$ . Comparing with standard vertex

form of equation $f(x)=a(x-h)^2+k ; (h,k)$ being vertex

we find here $h= -7/13 , k=-20 3/13 :.$ Vertex is at

$(-7/13 , -20 3/13)$ . Vertex form of equation is

$y=13( x+7/13)^2-20 3/13$ [Ans]

What is the vertex form of y=13x^2 + 14x + 24y=13x^2 + 14x + 24?